document.write( "Question 886476: Solving equations by completing the square!
\n" ); document.write( "r^2+2r-33=0. 6. a^2-2a-48=0. thank you! \n" ); document.write( "
Algebra.Com's Answer #535922 by lwsshak3(11628)\"\" \"About 
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Solving equations by completing the square!
\n" ); document.write( "r^2+2r-33=0. 6. a^2-2a-48=0.
\n" ); document.write( "***
\n" ); document.write( "r^2+2r-33=0
\n" ); document.write( "add 1/2 the coefficient of the r-term squared, then add (-1) to balance the equation.
\n" ); document.write( "(r^2+2r+1)-1-33=0
\n" ); document.write( "(x+1)^2=34
\n" ); document.write( "take sqrt of both sides
\n" ); document.write( "x+1=±√34
\n" ); document.write( "x=-1±√34
\n" ); document.write( "x=-1-√34
\n" ); document.write( "or
\n" ); document.write( "x=-1+√34
\n" ); document.write( "..
\n" ); document.write( "a^2-2a-48=0
\n" ); document.write( "add 1/2 the coefficient of the a-term squared, then add (-1) to balance the equation.
\n" ); document.write( "(a^2-2a+1)-1-48=0
\n" ); document.write( "(x-1)^2=49
\n" ); document.write( "take sqrt of both sides
\n" ); document.write( "x-1=±√49
\n" ); document.write( "x=1±7
\n" ); document.write( "x=-6
\n" ); document.write( "or
\n" ); document.write( "x=8 \n" ); document.write( "
\n" );