document.write( "Question 886476: Solving equations by completing the square!
\n" ); document.write( "r^2+2r-33=0. 6. a^2-2a-48=0. thank you! \n" ); document.write( "
Algebra.Com's Answer #535920 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "\"r%5E2%2B2r-33=0\"\r\n" );
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document.write( "Isolate the variable terms by\r\n" );
document.write( "adding 33 to both sides:\r\n" );
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document.write( "\"r%5E2%2B2r=33\"\r\n" );
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document.write( "[If there were a coefficient for \"r%5E2\" other than 1, you\r\n" );
document.write( "would divide thru by that coefficient.  But since the coefficient\r\n" );
document.write( "is 1, this is not necessary, but it might be in some problems.]\r\n" );
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document.write( "To the side, multiply the coefficient of r by \"1%2F2\".\r\n" );
document.write( "\"%282%29%2A%281%2F2%29=1\"\r\n" );
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document.write( "Now square \"1\".  \"1%5E2=1\"\r\n" );
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document.write( "Add \"1\" to both sides of the equation \"r%5E2%2B2r=33\"\r\n" );
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document.write( "\"r%5E2%2B2r%2B1=33%2B1\"\r\n" );
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document.write( "Combine the right side: \"33%2B1\"\r\n" );
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document.write( "\"r%5E2%2B2r%2B1=34\"\r\n" );
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document.write( "Factor the left side:\r\n" );
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document.write( "\"%28r%2B1%29%28r%2B1%29=34\"\r\n" );
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document.write( "Write the left side as the square of\r\n" );
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document.write( "\"%28r%2B1%29%5E2=34\"\r\n" );
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document.write( "Take the square root of both sides,\r\n" );
document.write( "remembering the ± on the right:\r\n" );
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document.write( "\"sqrt%28%28r%2B1%29%5E2%29+=+%22%22+%2B-+sqrt%2834%29\"\r\n" );
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document.write( "\"r%2B1\"=±\"sqrt%2834%29\"\r\n" );
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document.write( "\"x=-1+%2B-+sqrt%2834%29\"\r\n" );
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document.write( "Using the +\r\n" );
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document.write( "\"x=-1+%2B+sqrt%2834%29\"\r\n" );
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document.write( "Using the -\r\n" );
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document.write( "\"x=-1+-+sqrt%2834%29\"\r\n" );
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document.write( "The solutions are \"-1%2Bsqrt%2834%29\" and \"-1-sqrt%2834%29\"\r\n" );
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document.write( "Edwin
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