document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=886433>Question 886433</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given a circle U which has a center at coordinates (1,3) and a point on its circumference at (2, 2), what is the area of the circle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #535915 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39620)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=535915\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The radius will be size of the distance from (1,3) to (2,2).\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r=sqrt%28%281-2%29%5E2%2B%283-2%29%5E2%29 ALIGN=MIDDLE  ALT=\"r=sqrt%28%281-2%29%5E2%2B%283-2%29%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "and area of the circle is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2Ar%5E2=highlight_green%28pi%2A%28%281-2%29%5E2%2B%283-2%29%5E2%29%29 ALIGN=MIDDLE  ALT=\"pi%2Ar%5E2=highlight_green%28pi%2A%28%281-2%29%5E2%2B%283-2%29%5E2%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "Just needs simplification. </SPAN>\n" );
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