document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=74423>Question 74423</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2x+2y+3z=13<BR>\n" );
document.write( "-3x+4y-z=5<BR>\n" );
document.write( "5x-3y+z=2\r<BR>\n" );
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document.write( "solve a system of 3 linear equations in 3 variables by the addition method.  I keep coming up with fractions for x variable.  i must be missing something in one of steps. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #53591 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=53591\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> What's wrong with fractions?\r<BR>\n" );
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document.write( "adding (equation 2) to (equation 3) gives 2x+y=7 (a)\r<BR>\n" );
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document.write( "multiplying (equation 2) by 3 and adding it to (equation 1) gives -7x+14y=28, dividing this by 7 gives -x+2y=4 (b)\r<BR>\n" );
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document.write( "multiplying (equation (b)) by 2 and adding (equation (a)) gives 5y=15 \r<BR>\n" );
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document.write( "so y=3,, x=2,, and z=1 </SPAN>\n" );
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