document.write( "Question 886368: The side of one square is one inch longer than twice the length of the side of a aecond square.
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document.write( "The difference of the areas of the square is 96inē. Find the length of a side of each square. \n" );
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Algebra.Com's Answer #535897 by Theo(13342)![]() ![]() You can put this solution on YOUR website! x = side of square 1 \n" ); document.write( "2x+1 = side of square 2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "difference in the areas is equal to 96 square inches.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that would be area of square 2 minus area of square 1 = 96\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "area of square 1 = x^2 \n" ); document.write( "area of square 2 = (2x+1)^2 = 4x^2 + 4x + 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4x^2 + 4x + 1 - x^2 = 96\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "simplify to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3x^2 + 4x - 95 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "factor this to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x-5) * (3x+19) = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for x to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 5 or x = -19/3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x can't be negative, so your solution can only be x = 5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "replace x with 5 in the original equation to see if it holds true.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your original equation is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^2 = area of square 1 \n" ); document.write( "(2x+1)^2 = area of square 2 \n" ); document.write( "square 2 - square 1 = 96\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "replacing x with 5, we get: \n" ); document.write( "area of square 1 = 25 \n" ); document.write( "area of square 2 = 121 \n" ); document.write( "square 2 - square 1 area = 121 - 25 = 96\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 5 is your answer.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |