document.write( "Question 886368: The side of one square is one inch longer than twice the length of the side of a aecond square.
\n" ); document.write( "The difference of the areas of the square is 96inē. Find the length of a side of each square.
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Algebra.Com's Answer #535897 by Theo(13342)\"\" \"About 
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x = side of square 1
\n" ); document.write( "2x+1 = side of square 2\r
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\n" ); document.write( "\n" ); document.write( "difference in the areas is equal to 96 square inches.\r
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\n" ); document.write( "\n" ); document.write( "that would be area of square 2 minus area of square 1 = 96\r
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\n" ); document.write( "\n" ); document.write( "area of square 1 = x^2
\n" ); document.write( "area of square 2 = (2x+1)^2 = 4x^2 + 4x + 1\r
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\n" ); document.write( "\n" ); document.write( "you get:\r
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\n" ); document.write( "\n" ); document.write( "4x^2 + 4x + 1 - x^2 = 96\r
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\n" ); document.write( "\n" ); document.write( "simplify to get:\r
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\n" ); document.write( "\n" ); document.write( "3x^2 + 4x - 95 = 0\r
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\n" ); document.write( "\n" ); document.write( "factor this to get:\r
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\n" ); document.write( "\n" ); document.write( "(x-5) * (3x+19) = 0\r
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\n" ); document.write( "\n" ); document.write( "solve for x to get:\r
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\n" ); document.write( "\n" ); document.write( "x = 5 or x = -19/3\r
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\n" ); document.write( "\n" ); document.write( "x can't be negative, so your solution can only be x = 5\r
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\n" ); document.write( "\n" ); document.write( "replace x with 5 in the original equation to see if it holds true.\r
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\n" ); document.write( "\n" ); document.write( "your original equation is:\r
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\n" ); document.write( "\n" ); document.write( "x^2 = area of square 1
\n" ); document.write( "(2x+1)^2 = area of square 2
\n" ); document.write( "square 2 - square 1 = 96\r
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\n" ); document.write( "\n" ); document.write( "replacing x with 5, we get:
\n" ); document.write( "area of square 1 = 25
\n" ); document.write( "area of square 2 = 121
\n" ); document.write( "square 2 - square 1 area = 121 - 25 = 96\r
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\n" ); document.write( "\n" ); document.write( "x = 5 is your answer.\r
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