document.write( "Question 886386: The area of a rectangle is 42 ft. squared, , and the length of the rectangle is 11 ft. less than three times the width. Find the dimensions of the rectangle:\r
\n" ); document.write( "\n" ); document.write( "Length: ft.
\n" ); document.write( "Width: ft.\r
\n" ); document.write( "\n" ); document.write( "PLEASE HELP!
\n" ); document.write( "THANK YOU :) \n" ); document.write( "
Algebra.Com's Answer #535891 by stanbon(75887)\"\" \"About 
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The area of a rectangle is 42 ft. squared, , and the length of the rectangle is 11 ft. less than three times the width. Find the dimensions of the rectangle:
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\n" ); document.write( "Let width be \"x\"
\n" ); document.write( "Then length is \"3x-11\"
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\n" ); document.write( "Equation:
\n" ); document.write( "width*length = 42
\n" ); document.write( "x(3x-11) = 42
\n" ); document.write( "3x^2-11x-42 = 0
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\n" ); document.write( "x = [11+-sqrt(121-4*3*-42))]/6
\n" ); document.write( "x = [11+-sqrt(625)]/6
\n" ); document.write( "Positive solution:
\n" ); document.write( "x = (11+25)/6
\n" ); document.write( "x = 36/6 = 6 ft (width)
\n" ); document.write( "3x-11 = 18-11 = 7 ft (length)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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