document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=886381>Question 886381</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A vessel contains 20% solution of acetic acid and another vessel contains 50% solution of acetic acid. Mang Luis needs 300cc of 30% acetic acid. How many cc of each solution must he mix? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #535886 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=535886\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A vessel contains 20% solution of acetic acid and another vessel contains 50% solution of acetic acid. Mang Luis needs 300cc of 30% acetic acid. How many cc of each solution must he mix?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "acid + acid = acid<BR>\n" );
document.write( "0.20x + 0.50(300-x) = 0.30*300<BR>\n" );
document.write( "---<BR>\n" );
document.write( "20x + 50*300 - 50x = 30*300<BR>\n" );
document.write( "-30x = -20*300<BR>\n" );
document.write( "x = (2/3)300 = 200cc (amt. of 20% solution needed)<BR>\n" );
document.write( "300-x = 100cc (amt of 50% solution needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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