document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=886286>Question 886286</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2^(log_2(3)-log_8(9))=<BR>\n" );
document.write( "so far i used the change of base to get<BR>\n" );
document.write( "2^(ln3/ln8)=<BR>\n" );
document.write( "the answer is 3root3 ->^3&#8730;3 but i don't know how to get that from here. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #535880 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=535880\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> note that the logarithm quotient rule requires both logs to have the same base<BR>\n" );
document.write( "2^(log_2(3)-log_8(9)) = 2^( 1.5849625007 -  1.0566416671) =<BR>\n" );
document.write( "2^(0.528320834) = 1.44224957<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );