document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=886347>Question 886347</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if 'n' is odd, then prove that (x + 1) is a factor of x^n + 1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #535877 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=535877\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if x+1 is a factor of x^n+1, then x = -1 is a zero of x^n+1<BR>\n" );
document.write( "we are given that n is odd so x^n will be -1 and x^n+1 = 0 with x = -1<BR>\n" );
document.write( "therefore x+1 is a factor of x^n+1<BR>\n" );
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