document.write( "Question 886282: a collection of nickels and dimes is a total value of $2.00 and contains 25 coins. How many of each coin is in the collection? \n" ); document.write( "
Algebra.Com's Answer #535865 by JulietG(1812)![]() ![]() You can put this solution on YOUR website! If all 25 coins were dimes, the total would be 25 * 10 = $2.50 \n" ); document.write( "The actual total is $2.00 \n" ); document.write( "$2.50 - $2.00 = 50 cents \n" ); document.write( "The difference between a dime and a nickel is 5 cents \n" ); document.write( "50 cents / 5 cents = 10 \n" ); document.write( "There are ten nickels for a total of .50 \n" ); document.write( "If there are 25 coins and 10 are nickels, 15 must be dimes \n" ); document.write( "15 dimes at .10 each = $1.50 \n" ); document.write( "$1.50 (dimes) + .50 (nickels) = $2.00 \n" ); document.write( ">>15 dimes, 10 nickels \n" ); document.write( " |