document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=74474>Question 74474</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have tried this problem several times and keep seem to come up with the right formula:<BR>\n" );
document.write( "If I want to make the perfect 12 oz cup of chocolate milk, it requires that the mixture is 42% Hershey's Syrup. What I have right now is 8oz of a milk/syrup mixture that I know contains 30% syrup. What must the syrup concentration be in the remaining mixture that I must add in order to achieve perfection? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #53584 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=53584\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Yum--chocolate--my favorite!\r<BR>\n" );
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document.write( "12 oz of chocolate milk at 42% syrup means 12 X .42 or 5.04 oz of syrup\r<BR>\n" );
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document.write( "you currently have 8 oz at 30% or 2.4 oz of syrup\r<BR>\n" );
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document.write( "you need to add 5.04-2.4 or 2.64 0z of syrup in another 4 oz of mixture\r<BR>\n" );
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document.write( "this would be 2.64/4 or a 66% mixture\r<BR>\n" );
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document.write( "Happy sipping!! </SPAN>\n" );
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