document.write( "Question 886239: Two hikers start walking in opposite directions from the same place at the same time. The hiker heading west is walking 2 kilometers per hour faster than the hiker heading east. If they are 15 kilometers apart after 1.5 hours what is the rate of each hiker? Let x represent the rate of the westbound hiker and let y represent the rate of the eastbound hiker. \n" ); document.write( "
Algebra.Com's Answer #535776 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! Two hikers start walking in opposite directions from the same place at the same time. The hiker heading west is walking 2 kilometers per hour faster than the hiker heading east. If they are 15 kilometers apart after 1.5 hours what is the rate of each hiker? Let x represent the rate of the westbound hiker and let y represent the rate of the eastbound hiker. \n" ); document.write( ". \n" ); document.write( "Let x = rate of westbound hiker \n" ); document.write( "and y = rate of eastbound hiker \n" ); document.write( ". \n" ); document.write( "From: \"The hiker heading west is walking 2 kilometers per hour faster than the hiker heading east.\" \n" ); document.write( "x = y+2 (equation 1) \n" ); document.write( "From: \"they are 15 kilometers apart after 1.5 hours\" we have \n" ); document.write( "1.5(x+y) = 15 (equation 2) \n" ); document.write( "substitute value of x from equation 1 into equation 2: \n" ); document.write( "1.5(x+y) = 15 \n" ); document.write( "1.5(y+2+y) = 15 \n" ); document.write( "1.5(2y+2) = 15 \n" ); document.write( "2y+2 = 10 \n" ); document.write( "2y = 8 \n" ); document.write( "y = 4 kph (rate of eastbound hiker) \n" ); document.write( ". \n" ); document.write( "rate of westbound hiker: \n" ); document.write( "x = y+2 \n" ); document.write( "x = 4+2 \n" ); document.write( "x = 6 kph \n" ); document.write( " |