document.write( "Question 886239: Two hikers start walking in opposite directions from the same place at the same time. The hiker heading west is walking 2 kilometers per hour faster than the hiker heading east. If they are 15 kilometers apart after 1.5 hours what is the rate of each hiker? Let x represent the rate of the westbound hiker and let y represent the rate of the eastbound hiker. \n" ); document.write( "
Algebra.Com's Answer #535775 by JulietG(1812)\"\" \"About 
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Distance per hour = 15 km/1.5 kmh, or 10 kmh
\n" ); document.write( "X + Y = 10
\n" ); document.write( "Y = X + 2 (he is slower by 2)
\n" ); document.write( "Substitute the known value of Y from the second equation into the first.
\n" ); document.write( "X + Y = 10
\n" ); document.write( "X + (X+2) = 10
\n" ); document.write( "2X + 2 = 10
\n" ); document.write( "2X = 8
\n" ); document.write( "X = 4
\n" ); document.write( "The slower hiker is traveling 4kmh. Therefore the faster hiker is traveling 6khm.
\n" ); document.write( ".
\n" ); document.write( "Prove it:
\n" ); document.write( "Hiker X travels 4 * 1.5 hours, or 6 km
\n" ); document.write( "Hiker Y travels 6 * 1.5, or 9 km
\n" ); document.write( "6 + 9 = 15 km in 1.5 hours
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