document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=886231>Question 886231</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 2cm longer than it's width. If the perimeter of the rectangle is 44 cm, find it's area </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #535767 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=535767\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter is a fence around.  P = 2L + 2W<BR>\n" );
document.write( "L = W + 2<BR>\n" );
document.write( "Take the known value of the length from the second equation and substitute it into the first.<BR>\n" );
document.write( "P = 2L + 2W<BR>\n" );
document.write( "44 = 2L + 2W<BR>\n" );
document.write( "44 = 2(W+2) + 2W<BR>\n" );
document.write( "Distribute<BR>\n" );
document.write( "44 = 2W + 4 + 2W<BR>\n" );
document.write( "44 = 4W + 4<BR>\n" );
document.write( "Subtract 4 from each side<BR>\n" );
document.write( "40 = 4W<BR>\n" );
document.write( "Divide each side by 4<BR>\n" );
document.write( "10 = W<BR>\n" );
document.write( ".<BR>\n" );
document.write( "If the width is 10, the length is 10+2, or 12<BR>\n" );
document.write( "10 + 10 (two widths) + 12 + 12 (two lengths) = 44<BR>\n" );
document.write( "Success! </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );