document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=886204>Question 886204</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this problem.<BR>\n" );
document.write( "The length of a rectangle is three times its width. If its length is increased by 2m and its width is decreased by 1m, the area of the new rectangle is 68m^2. Find the dimensions of the original rectangle.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #535764 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=535764\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let w be width, then length = 3w<BR>\n" );
document.write( "Area of rectangle(A) = length times width<BR>\n" );
document.write( "68 = (3w+2) * (w-1)<BR>\n" );
document.write( "68 = 3w^2 -w -2<BR>\n" );
document.write( "subtract 68 from both sides of =<BR>\n" );
document.write( "3w^2 -w -70 = 0<BR>\n" );
document.write( "(3w+14) * (w-5) = 0<BR>\n" );
document.write( "w = -14/3 or 5<BR>\n" );
document.write( "we want the positive value for w<BR>\n" );
document.write( "therefore the length = 15 and width = 5<BR>\n" );
document.write( "check answer<BR>\n" );
document.write( "68 = (15+2) * (5-1) = 17 * 4 = 68<BR>\n" );
document.write( "our answer checks<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );