document.write( "Question 886214: According to R.L. Polk & Co., the average age of cars and light trucks in the U.S. in 2011 was 10.8 years. Assume the standard deviation for this population is 3.7 years. A sample of 35 randomly selected vehicles was selected. What is the probability that the sample mean will be greater than 10 years?
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document.write( "A. 0.5469
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document.write( "B. 0.7812
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document.write( "C. 0.8997
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document.write( "D. 0.9846
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document.write( " \n" );
document.write( "
Algebra.Com's Answer #535760 by stanbon(75887) ![]() You can put this solution on YOUR website! According to R.L. Polk & Co., the average age of cars and light trucks in the U.S. in 2011 was 10.8 years. Assume the standard deviation for this population is 3.7 years. A sample of 35 randomly selected vehicles was selected. What is the probability that the sample mean will be greater than 10 years? \n" ); document.write( "z(10) = (10-10.8)/(3.7/sqrt(35)) = -0.0365 \n" ); document.write( "P(x-bar > 10) = P(z > -0.0365) = normalcdf(-0.0365,100) = 0.5146 \n" ); document.write( "------------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "========================= \n" ); document.write( " A. 0.5469 \n" ); document.write( " B. 0.7812 \n" ); document.write( " C. 0.8997 \n" ); document.write( " D. 0.9846 \n" ); document.write( " \n" ); document.write( " |