document.write( "Question 885807: Multiply each of the polynomial by x+1 with solution:
\n" ); document.write( "a. x-1
\n" ); document.write( "b. x^2-x+1
\n" ); document.write( "c. x^3-x^2+x-1
\n" ); document.write( "d. x^4-x^3+x^2-x+1
\n" ); document.write( "2. Look for the pattern in Question 1 and use it to multiply:
\n" ); document.write( "(x+1) (x^8-x^7+x^6-x^5+x^4-x^3+x^2-x+1)
\n" ); document.write( "3. Predict what you think will be the product of (x+1) and (x^100-x^98+x^97...x^2-x+1) when simplified, can you explain why you're must be correct?
\n" ); document.write( "All should have a solution. Please help. :)
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Algebra.Com's Answer #535747 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
1)
\n" ); document.write( "\"%28x%2B1%29%2A%28x-1%29=x%2A%28x-1%29%2B1%2A%28x-1%29=x%5E2-x%2Bx-1=x%5E2-1\"
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\n" ); document.write( "=?
\n" ); document.write( "Those two products would be too long to write in one line, so I will add them up vertically:
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\n" ); document.write( "So, \"%28x%2B1%29%2A%28x%5E4-x%5E3%2Bx%5E2-x%2B1%29=X%5E6%2B1\"
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\n" ); document.write( "2) In all the products above \"%28x%2B1%29\" is one factor,
\n" ); document.write( "and the other factor is a polynomial with sign that alternate,
\n" ); document.write( "so all the middle products cancel out.
\n" ); document.write( "You are left with just the product of the first terms plus the product of the last terms.
\n" ); document.write( "So, \"%28x%2B1%29%2A%28x%5E8-x%5E7%2Bx%5E6-x%5E5%2Bx%5E4-x%5E3%2Bx%5E2-x%2B1%29=x%5E9%2B1\"
\n" ); document.write( "All the other products cancel out and you are left with the product of the \"x\" in \"%28x%2B1%29\" times the \"x%5E8\" ,
\n" ); document.write( "plus the product of the \"%22%2B1%22\" and \"%22%2B1%22\" at the end of both factors.
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\n" ); document.write( "3) I believe what you meant to write was
\n" ); document.write( "\"%28x%2B1%29%2A%28x%5E100-x%5E99%2Bx%5E98-x%5E97%2B+%22...%22+%2Bx%5E2-x%2B1%29\" , because if the signs alternate,
\n" ); document.write( "all the terms with even exponents will follow a \"%22%2B%22\" sign.
\n" ); document.write( "\"%28x%2B1%29%2A%28x%5E100-x%5E99%2Bx%5E98-x%5E97%2B+%22...%22+%2Bx%5E2-x%2B1%29=x%5E101%2B1\"
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