document.write( "Question 886036: Solve the equation on the interval [0,2pi)
\n" ); document.write( "2sin^2x=-3sinx+5, in terms of pi and use integers and/or fractions\r
\n" ); document.write( "\n" ); document.write( "I have tried making the equation equal to 0, but when I try to simplify, the sin^2x is confusing me. Please explain how this problem works out. Thank you in advance!
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Algebra.Com's Answer #535731 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
Solve the equation on the interval [0,2pi)
\n" ); document.write( "2sin^2x=-3sinx+5, in terms of pi and use integers and/or fractions
\n" ); document.write( "***
\n" ); document.write( "\"2sin%5E2%28x%29=-3sin%28x%29%2B5\"
\n" ); document.write( "\"2sin%5E2%28x%29%2B3sin%28x%29-5=0\"
\n" ); document.write( "\"%282sin%28x%29%2B5%29%28sin%28x%29-1%29=0\"
\n" ); document.write( "2sin(x)+5=0
\n" ); document.write( "sin(x)=-5/2(reject,(-1 < sin(x) < 1))
\n" ); document.write( "or
\n" ); document.write( "sin(x)-1=0
\n" ); document.write( "sin(x)=1
\n" ); document.write( "x=π/2
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