document.write( "Question 886036: Solve the equation on the interval [0,2pi)
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document.write( "2sin^2x=-3sinx+5, in terms of pi and use integers and/or fractions\r
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document.write( "I have tried making the equation equal to 0, but when I try to simplify, the sin^2x is confusing me. Please explain how this problem works out. Thank you in advance!
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Algebra.Com's Answer #535731 by lwsshak3(11628) ![]() You can put this solution on YOUR website! Solve the equation on the interval [0,2pi) \n" ); document.write( "2sin^2x=-3sinx+5, in terms of pi and use integers and/or fractions \n" ); document.write( "*** \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "2sin(x)+5=0 \n" ); document.write( "sin(x)=-5/2(reject,(-1 < sin(x) < 1)) \n" ); document.write( "or \n" ); document.write( "sin(x)-1=0 \n" ); document.write( "sin(x)=1 \n" ); document.write( "x=π/2 \n" ); document.write( " |