document.write( "Question 886167: A mother is 20 years older than her son. Ten years ago she was 3 times as old as her son then. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #535728 by lwsshak3(11628)\"\" \"About 
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A mother is 20 years older than her son. Ten years ago she was 3 times as old as her son then. Find their present ages.
\n" ); document.write( "***
\n" ); document.write( "let x=son's age
\n" ); document.write( "x+20=mother's age
\n" ); document.write( "..
\n" ); document.write( "10 yrs ago:
\n" ); document.write( "x-10=son's age
\n" ); document.write( "x+20-10=x+10=mother's age
\n" ); document.write( "x+10=3(x-10)
\n" ); document.write( "x+10=3x-30
\n" ); document.write( "2x=40
\n" ); document.write( "x=20
\n" ); document.write( "x+20=40
\n" ); document.write( "son's age=20
\n" ); document.write( "mother's age=40
\n" ); document.write( "
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