document.write( "Question 886167: A mother is 20 years older than her son. Ten years ago she was 3 times as old as her son then. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #535728 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! A mother is 20 years older than her son. Ten years ago she was 3 times as old as her son then. Find their present ages. \n" ); document.write( "*** \n" ); document.write( "let x=son's age \n" ); document.write( "x+20=mother's age \n" ); document.write( ".. \n" ); document.write( "10 yrs ago: \n" ); document.write( "x-10=son's age \n" ); document.write( "x+20-10=x+10=mother's age \n" ); document.write( "x+10=3(x-10) \n" ); document.write( "x+10=3x-30 \n" ); document.write( "2x=40 \n" ); document.write( "x=20 \n" ); document.write( "x+20=40 \n" ); document.write( "son's age=20 \n" ); document.write( "mother's age=40 \n" ); document.write( " |