document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=886149>Question 886149</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one number is 8 less than another number. If the sum of the two numbers is 96 find the two numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #535713 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=535713\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A = B-8<BR>\n" );
document.write( "A + B = 96<BR>\n" );
document.write( "Substitute the value of A in the top equation into the bottom.<BR>\n" );
document.write( "A + B = 96<BR>\n" );
document.write( "(B-8) + B = 96<BR>\n" );
document.write( "2B - 8 = 96<BR>\n" );
document.write( "Add 8 to each side<BR>\n" );
document.write( "2B = 104<BR>\n" );
document.write( "Divide each side by 2<BR>\n" );
document.write( "B = 52<BR>\n" );
document.write( "Since A is B-8, A is therefore 52-8, or 44<BR>\n" );
document.write( "44 + 52 = 96 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );