document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=886152>Question 886152</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 72 inches. If the length of the rectangle is nine inches more than two times the width, find the dimensions. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #535711 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=535711\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter (fence around) = 2L + 2W<BR>\n" );
document.write( "L = 2W + 9<BR>\n" );
document.write( "Substitute the value of L from the bottom equation into the top.<BR>\n" );
document.write( "72 = 2L + 2W<BR>\n" );
document.write( "72 = 2(2W+9) + 2W<BR>\n" );
document.write( "Distribute<BR>\n" );
document.write( "72 = 4W + 18 + 2W<BR>\n" );
document.write( "Add<BR>\n" );
document.write( "72 = 6W + 18<BR>\n" );
document.write( "Subtract 18 from each side<BR>\n" );
document.write( "54 = 6W<BR>\n" );
document.write( "Divide each side by 6<BR>\n" );
document.write( "9 = W<BR>\n" );
document.write( ".<BR>\n" );
document.write( "If the width is 9, then the length is (2*9)+9 = 27<BR>\n" );
document.write( "27 + 27 + 9 + 9 = 72 (perimeter = 2*length + 2*width) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );