document.write( "Question 885923: A tight end can run the 100 yard dash in 20 seconds
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document.write( "A defensive back can do it in 15 seconds
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document.write( "The tight end catches a pass at his own 20 yard line with the defensive back at the 15 yard line.
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document.write( "If no other players are nearby, at what yard line will the defensive back catch up to the tight end?
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document.write( "[hint: At time t=0, the defensive back is 5 yards behind the tight end.]
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Algebra.Com's Answer #535693 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A tight end can run the 100 yard dash in 20 seconds \n" ); document.write( "A defensive back can do it in 15 seconds \n" ); document.write( "The tight end catches a pass at his own 20 yard line with the defensive back at the 15 yard line. \n" ); document.write( "If no other players are nearby, at what yard line will the defensive back catch up to the tight end? \n" ); document.write( "[hint: At time t=0, the defensive back is 5 yards behind the tight end.] \n" ); document.write( ": \n" ); document.write( "Find the speeds in yd/sec \n" ); document.write( "100/20 = 5 yd/sec \n" ); document.write( "100/15 = 6.67 yd/sec \n" ); document.write( ": \n" ); document.write( "Write a distance equation; dist = speed * time \n" ); document.write( ": \n" ); document.write( "When the back tackles the t.e, the back will travel 5 yds more than t.E \n" ); document.write( "6.67t = 5t + 5 \n" ); document.write( "6.67t - 5t = 5 \n" ); document.write( "1.67t = 5 \n" ); document.write( "t = 5/1.67 \n" ); document.write( "t = 3 sec \n" ); document.write( "Find how many yds the back travels in 3 sec \n" ); document.write( "3 * 6.67 = 20 yds \n" ); document.write( "therefore \n" ); document.write( "15 + 20 = 35 yd line, the back tackles the t.e \n" ); document.write( " |