document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=886072>Question 886072</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangular field is  358 yards. If the width of the field is 83 yards, what is its length? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #535645 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=535645\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangular field is  358 yards. If the width of the field is 83 yards, what is its length?<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Since perimeter is<BR>\n" );
document.write( "2(W+L)<BR>\n" );
document.write( "And, they give us the width and perimeter we get:<BR>\n" );
document.write( "2(83+L) = 358<BR>\n" );
document.write( "(83+L) = 179<BR>\n" );
document.write( "L = 179-83<BR>\n" );
document.write( "L = 96 yards (length)<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );