document.write( "Question 886054: factor the expression: x^3+2x^2-3x-6 \n" ); document.write( "

Algebra.Com's Answer #535629 by Theo(13342) $\"\"$ $\"About$

You can put this solution on YOUR website!
start with:
\n" ); document.write( "x^3 + 2x^2 -3x - 6
\n" ); document.write( "separate into 2 sections as shown below:
\n" ); document.write( "(x^3 + 2x^2 - (3x + 6)
\n" ); document.write( "factor out x^2 from the section on the left and factor out 3 from the section on the right to get:
\n" ); document.write( "x^2 * (x + 2) - 3 * (x + 2)
\n" ); document.write( "factor out the common term of (x + 2) to get:
\n" ); document.write( "(x^2 - 3) * (x + 2)
\n" ); document.write( "those are your factors.
\n" ); document.write( "theoretically (x^2 - 3) can also be factored as (x - sqrt(3)) * (x + sqrt(3)) but i'm not sure they want you to go that far.
\n" ); document.write( "you would get:
\n" ); document.write( "(x - sqrt(3)) * (x + sqrt(3)) * (x + 2)\r
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