document.write( "Question 74583: What quantity of 60% acid solution must be mixed with 30% solution to produce 300mL of a 50% solution? \n" ); document.write( "

Algebra.Com's Answer #53561 by Nate(3500) $\"\"$ $\"About$

You can put this solution on YOUR website!
(x(60%) + (300 - x)(30%))/(300) = 50%
\n" ); document.write( "(x(0.6) + (300 - x)(0.3))/(300) = 0.5
\n" ); document.write( "0.6x + 90 - 0.3x = 150
\n" ); document.write( "0.3x = 60
\n" ); document.write( "x = 200
\n" ); document.write( "200mL of 60% and 100mL of 30% \n" ); document.write( "

\n" );