document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=885927>Question 885927</A>: <I><SPAN STYLE=\"word-break: break-all;\"> CRA CDs Inc. wants the mean lengths of the \"cuts\" on a CD to be 154 seconds (2 minutes and 34 seconds). This will allow the disk jockeys to have plenty of time for commercials within each 10-minute segment. Assume the distribution of the length of the cuts follows the normal distribution with a population standard deviation of 6 seconds. Suppose we select a sample of 23 cuts from various CDs sold by CRA CDs Inc.\r<BR>\n" );
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document.write( "a.What can we say about the shape of the distribution of the sample mean<BR>\n" );
document.write( "b.What is the standard error of the mean?<BR>\n" );
document.write( "c.What percent of the sample means will be greater than 156 seconds?<BR>\n" );
document.write( "d.What percent of the sample means will be greater than 149 but less than 156 seconds </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #535598 by </B><A HREF=/tutors/aboutme.mpl?userid=oscargut><B>oscargut(2103)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oscargut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=oscargut><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=535598\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a)\r<BR>\n" );
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document.write( "The sample mean has a normal distribution\r<BR>\n" );
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document.write( "b)\r<BR>\n" );
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document.write( "standard error of the sample mean is: 6/sqrt(23)\r<BR>\n" );
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document.write( "You can ask me more at:\r<BR>\n" );
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document.write( "mthman@gmail.com\r<BR>\n" );
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document.write( "Thanks </SPAN>\n" );
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