document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=885967>Question 885967</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A MAN IS 3 TIMES AS OLD AS HIS SON,4 YEARS AGO,THE SUM OF THEIR AGES WAS 24.FIND THEIR PRESENT AGES   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #535587 by </B><A HREF=/tutors/aboutme.mpl?userid=pj66><B>pj66(7)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=pj66><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=535587\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the present age of son.<BR>\n" );
document.write( "=> father's age = 3*x<BR>\n" );
document.write( "Four years ago,<BR>\n" );
document.write( "father's age = 3*x - 4 and son's age = x-4<BR>\n" );
document.write( "Sum of their ages is 24<BR>\n" );
document.write( "=> 3*x-4+x-4=24<BR>\n" );
document.write( "=> 4*x-8=24<BR>\n" );
document.write( "=> 4*x=32<BR>\n" );
document.write( "=> x=8<BR>\n" );
document.write( "Hence, father's present age is 24. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );