document.write( "Question 885944: you want to invest 10,000 dollars. how long will it take to double your investment at an annual interest rate of 10% compounded continuously?(round your answer to the nearest year)
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Algebra.Com's Answer #535571 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
One fast shortcut is the rule of 72. Divide 72 by 10 (ignore the percent) to get 72/10 = 7.2\r
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\n" ); document.write( "\n" ); document.write( "So it takes roughly 7.2 years\r
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\n" ); document.write( "\n" ); document.write( "Let's use the formula to get a more accurate answer:\r
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\n" ); document.write( "\n" ); document.write( "A = P*e^(r*t)\r
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\n" ); document.write( "\n" ); document.write( "20000 = 10000*e^(0.10*t)\r
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\n" ); document.write( "\n" ); document.write( "20000/10000 = e^(0.10*t)\r
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\n" ); document.write( "\n" ); document.write( "2 = e^(0.10*t)\r
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\n" ); document.write( "\n" ); document.write( "ln(2) = ln(e^(0.10*t))\r
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\n" ); document.write( "\n" ); document.write( "ln(2) = 0.10*t*ln(e)\r
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\n" ); document.write( "\n" ); document.write( "ln(2) = 0.10*t*1\r
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\n" ); document.write( "\n" ); document.write( "ln(2) = 0.10*t\r
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\n" ); document.write( "\n" ); document.write( "0.10*t = ln(2) \r
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\n" ); document.write( "\n" ); document.write( "t = ln(2)/0.10\r
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\n" ); document.write( "\n" ); document.write( "t = 6.93147180559946\r
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\n" ); document.write( "\n" ); document.write( "t = 7 ... round to the nearest whole number\r
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\n" ); document.write( "\n" ); document.write( "So it takes approximately 7 years (which is reasonably close to 7.2)\r
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\n" ); document.write( "\n" ); document.write( "The final answer is 7 since they want you to use the formula and round to the nearest year. However, it's always good to know a fast shortcut such as the rule of 72.
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