document.write( "Question 885922: An oil tanker can be emptied by the main pump in 4 hours. An auxiliary pump can empty the tanker in 7 hours. If the main pump is started at 8PM, when should the auxiliary pump be started so that the tanker is emptied by 11PM? \n" ); document.write( "
Algebra.Com's Answer #535558 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! The rate of emptying for main pump is: \n" ); document.write( " \n" ); document.write( "The rate of emptying for auxiliary pump is: \n" ); document.write( " \n" ); document.write( "-------------------------- \n" ); document.write( "8 PM to 11 PM is \n" ); document.write( "Let \n" ); document.write( " \n" ); document.write( "-------------------------- \n" ); document.write( "For main pump alone: \n" ); document.write( "fraction of tanker emptied = \n" ); document.write( " \n" ); document.write( "-------------------------- \n" ); document.write( "With both pumps on: \n" ); document.write( " \n" ); document.write( "Multiply both sides by \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "---------------- \n" ); document.write( "The auxiliary pump should be started at: \n" ); document.write( "8 PM + 1.25 hrs = 9:15 PM \n" ); document.write( "------------------------ \n" ); document.write( "check: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "OK \n" ); document.write( " \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |