document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=885873>Question 885873</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If X is a normal random variable with standard deviation 2.50, and if the probability that X is more than 6.95 is .1271, then what is the mean of x? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #535505 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=535505\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 0.1271 = 1 - Pr(X<6.95)<BR>\n" );
document.write( "Pr(X<6.95) = 1 - 0.1271 = 0.8729<BR>\n" );
document.write( "The z-value associated with 0.8729 = 1.14<BR>\n" );
document.write( "1.14 = (6.95 - mean) / 2.50<BR>\n" );
document.write( "6.95 - mean = 2.85<BR>\n" );
document.write( "mean = 6.95 - 2.85 = 4.1<BR>\n" );
document.write( " </SPAN>\n" );
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