document.write( "Question 885816: use Gauss approach to find the following signs (do not use formulas0.\r
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document.write( "a. 1+2+3+4+...+98
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document.write( "b. 1+3+5+7+...+1003\r
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document.write( "The sum of the sequence is \n" );
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Algebra.Com's Answer #535495 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! a) 1 +2 +3 +4 +......+98 \n" ); document.write( " 98 +97 +96 +95+......+1 \n" ); document.write( "sum 99 +99 +99 +99+......+99 \n" ); document.write( "there are 98 of these sums, the total is 98 * 99 = 9702, since this sum is twice the sum of the numbers 1 thru 98, we have \n" ); document.write( "sum 1 +2 +3 +4 +.....98 = 9702/2 = 4851 \n" ); document.write( "b) 1 +3 +5 +7+.....+1003 \n" ); document.write( " 1003 +1001 + 999 +997 +....+1 \n" ); document.write( "sum 1004 +1004 +1004 +1004 +..1004 \n" ); document.write( "There are 502 of these sums. the total is 502 * 1004 = 504008, since this sum is twice the sum of the numbers 1 +3 +5 +7 +....1003, we have \n" ); document.write( "sum 1 +3 +5 +7+.....+1003 = 504008/2 = 252004 \n" ); document.write( " \n" ); document.write( " |