document.write( "Question 74575: I don't get how to find the zeros or what the x=-3 is for.
\n" ); document.write( "f(x)=x^4+2x^3-13x^2-38x-24 and one x=-3? All zeros are needed to be found.
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Algebra.Com's Answer #53549 by checkley75(3666)\"\" \"About 
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F(-3)=(-3^4)+(2*-3^3)-(13*-3^2)-(38*-3)-24
\n" ); document.write( "F(-3)=81-54-117+114-24
\n" ); document.write( "F(-3)=81+114-54-117-24
\n" ); document.write( "F(-3)=195-195
\n" ); document.write( "F(-3)=0 ANSWER.
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