document.write( "Question 74575: I don't get how to find the zeros or what the x=-3 is for.
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document.write( "f(x)=x^4+2x^3-13x^2-38x-24 and one x=-3? All zeros are needed to be found. \n" );
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Algebra.Com's Answer #53549 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! F(-3)=(-3^4)+(2*-3^3)-(13*-3^2)-(38*-3)-24 \n" ); document.write( "F(-3)=81-54-117+114-24 \n" ); document.write( "F(-3)=81+114-54-117-24 \n" ); document.write( "F(-3)=195-195 \n" ); document.write( "F(-3)=0 ANSWER. \n" ); document.write( " |