document.write( "Question 885820: Joe’s rectangular backyard has an area of 3,100 ft 2. If the length of his yard is 12 ft more than the width, what are the dimensions of his yard? PLEASE HELP!!
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Algebra.Com's Answer #535462 by lwsshak3(11628) $\"\"$ $\"About$

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Joe’s rectangular backyard has an area of 3,100 ft 2. If the length of his yard is 12 ft more than the width, what are the dimensions of his yard?
\n" ); document.write( "***
\n" ); document.write( "let x=width
\n" ); document.write( "x+12=length
\n" ); document.write( "length*width=area
\n" ); document.write( "..
\n" ); document.write( "x(x+12)=3100
\n" ); document.write( "x^2+12x-3100=0
\n" ); document.write( "(x-50)(x+62)=0
\n" ); document.write( "x=-62 (reject)
\n" ); document.write( "or
\n" ); document.write( "x=50
\n" ); document.write( "x+12=62
\n" ); document.write( "dimensions of his yard:50 ft by 62 ft \n" ); document.write( "

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