document.write( "Question 885800: hi I need help with the following word problem:\r
\n" ); document.write( "\n" ); document.write( "An excursion boat travels upriver to a landing and then returns to its starting point. The trip upriver takes 1.2 hr and the trip back takes .9 hr. If the average speed on the return trip is 5 mph faster than on the trip upriver, what is the boats speed upriver?
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Algebra.Com's Answer #535453 by ankor@dixie-net.com(22740)\"\" \"About 
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An excursion boat travels upriver to a landing and then returns to its starting point.
\n" ); document.write( " The trip upriver takes 1.2 hr and the trip back takes .9 hr.
\n" ); document.write( " If the average speed on the return trip is 5 mph faster than on the trip upriver, what is the boats speed upriver?
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\n" ); document.write( "let s = the speed upriver
\n" ); document.write( "then
\n" ); document.write( "(s+5) = speed down river
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\n" ); document.write( "Write a distance equation; dist = time * speed
\n" ); document.write( "dist up = dist down
\n" ); document.write( "1.2s = .9(s+5)
\n" ); document.write( "1.2s = .9s + 4.5
\n" ); document.write( "1.2s - .9s = 4.5
\n" ); document.write( ".3s = 4.5
\n" ); document.write( "s = 4.5/.3
\n" ); document.write( "s = 15 mph is the distance upriver
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\n" ); document.write( "Confirm this by finding the distance at each speed, should be equal
\n" ); document.write( "1.2(15) = 18 mi
\n" ); document.write( ".9(20) = 18 mi
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