document.write( "Question 885759: If. A(-8;6),B,C and D(3;9) are vertices of a rhombus. The equation for AC is 3y=-x+10\r
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Algebra.Com's Answer #535438 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "The green line is the line 3y=-x+10\r\n" );
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document.write( "As you can see from the graphs below, there are two possible \r\n" );
document.write( "solutions for the rhombus.\r\n" );
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document.write( "There is a mistake in your problem, for as you see the line BD cannot\r\n" );
document.write( "possibly pass through the origin, yet the problem states:\r\n" );
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document.write( "\"Show that BD is 3x-y=0\"\r\n" );
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document.write( "But 3x-y=0 passes through the origin (0,0), so there is no way that\r\n" );
document.write( "3x-y=0 could be the equation of BD. \r\n" );
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document.write( "Let's find what the equation of BD really is.  \r\n" );
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document.write( "BD is parallel to AC and has the same slope.\r\n" );
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document.write( "AC has the equation  \"3y\"\"%22%22=%22%22\"\"-x%2B10\"\r\n" );
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document.write( "Solving for y,  \"y\"\"%22%22=%22%22\"\"expr%28-1%2F3%29x%2B10\"\r\n" );
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document.write( "thus the slope of AC and BD is \"-1%2F3\"\r\n" );
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document.write( "And BD passes through D(3,9)\r\n" );
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document.write( "Using the point-slope formula:\r\n" );
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document.write( "\"y-y%5B1%5D\"\"%22%22=%22%22\"\"m%28x-x%5B1%5D%29\"\r\n" );
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document.write( "\"y-9\"\"%22%22=%22%22\"\"expr%28-1%2F3%29%28x-3%29\"\r\n" );
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document.write( "Multiply through by 3\r\n" );
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document.write( "\"3y-27\"\"%22%22=%22%22\"{{-{x-3)}}} \r\n" );
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document.write( "\"3y-27\"\"%22%22=%22%22\"{{-x+3}}}\r\n" );
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document.write( "\"3y%2Bx\"\"%22%22=%22%22\"\"24\"\r\n" );
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document.write( "This is correct equation for BD, not 3y-x=0.  \r\n" );
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document.write( "Now we must find the coordinates of the K, the intersection of the\r\n" );
document.write( "diagonals.  Since the diagonals of a parallellogram bisect each other,\r\n" );
document.write( "we only need to find the midpoint of one of the diagonals.  We will\r\n" );
document.write( "need to find the coordinates of C, and then K will be the midpoint of\r\n" );
document.write( "diagonal CD. \r\n" );
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document.write( "Since this is a rhombus, all sides must be equal.  So we find side \r\n" );
document.write( "AD using the distance formula:\r\n" );
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document.write( "\"d\"\"%22%22=%22%22\"\"+sqrt%28+%28x%5B2%5D-x%5B1%5D%29%5E2+%2B+%28y%5B2%5D-y%5B1%5D%29%5E2%29\" \r\n" );
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document.write( "\"AD\"\"%22%22=%22%22\"\"+sqrt%28+%289-6%29%5E2+%2B+%283-%28-8%29%29%5E2%29\"\r\n" );
document.write( "\"AD\"\"%22%22=%22%22\"\"+sqrt%28+%283%29%5E2+%2B+%283%2B8%29%5E2%29\"\r\n" );
document.write( "\"AD\"\"%22%22=%22%22\"\"+sqrt%28+9+%2B+%2811%29%5E2%29\"\r\n" );
document.write( "\"AD\"\"%22%22=%22%22\"\"+sqrt%28+9+%2B+121%29\"\r\n" );
document.write( "\"AD\"\"%22%22=%22%22\"\"+sqrt%28130%29\"\r\n" );
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document.write( "So the length of all 4 sides is \"%22%22=%22%22\"\"+sqrt%28+%28x%5B2%5D-x%5B1%5D%29%5E2+%2B+%28y%5B2%5D-y%5B1%5D%29%5E2%29\" \r\n" );
document.write( "\"sqrt%28130%29\"\"%22%22=%22%22\"\"+sqrt%28+%28p-%28-8%29%29%5E2+%2B+%28q-6%29%5E2%29\"\r\n" );
document.write( "\"sqrt%28130%29\"\"%22%22=%22%22\"\"+sqrt%28+%28p%2B8%29%5E2+%2B+%28q-6%29%5E2%29\" \r\n" );
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document.write( "Square both sides:\r\n" );
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document.write( "\"130\"\"%22%22=%22%22\"\"%28p%2B8%29%5E2+%2B+%28q-6%29%5E2\"\r\n" );
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document.write( "Now we must solve this system of equations to find p and q,\r\n" );
document.write( "the coordinates of C\r\n" );
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document.write( "\"system%283q+=+-p%2B10%2C+130=%28p%2B8%29%5E2+%2B+%28q-6%29%5E2%29\"\r\n" );
document.write( "Solve the first equation for p, p = 10-3q\r\n" );
document.write( "Substitute in the second equation,\r\n" );
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document.write( "\"130\"\"%22%22=%22%22\"\"%28p%2B8%29%5E2+%2B+%28q-6%29%5E2\"\r\n" );
document.write( "\"130\"\"%22%22=%22%22\"\"%2810-3q%2B8%29%5E2+%2B+%28q-6%29%5E2\"\r\n" );
document.write( "\"130\"\"%22%22=%22%22\"\"%2818-3q%29%5E2+%2B+%28q-6%29%5E2\"\r\n" );
document.write( "\"130\"\"%22%22=%22%22\"\"9q%5E2-108q%2B324+%2B+q%5E2-12q%2B36\"\r\n" );
document.write( "\"130\"\"%22%22=%22%22\"\"10q%5E2-120q%2B360\"\r\n" );
document.write( "\"%220%22\"\"%22%22=%22%22\"\"10q%5E2-120q%2B230\"\r\n" );
document.write( "Divide through by 10\r\n" );
document.write( "\"%220%22\"\"%22%22=%22%22\"\"q%5E2-12q%2B23\"\r\n" );
document.write( "Solve by the quadratic formula and get\r\n" );
document.write( "\"q\"\"%22%22=%22%22\"\"6+%2B-+sqrt%2813%29\"\r\n" );
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document.write( "using the +, substitute in\r\n" );
document.write( "\"p\"\"%22%22=%22%22\"\"10-3q\"\r\n" );
document.write( "\"p\"\"%22%22=%22%22\"\"+10-3%286%2Bsqrt%2813%29%29+%5D\"\r\n" );
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document.write( "\"p\"\"%22%22=%22%22\"\"10-18-3sqrt%2813%29%29\"\r\n" );
document.write( "\"p\"\"%22%22=%22%22\"\"-8-3sqrt%2813%29%29\"\r\n" );
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document.write( "So point C in the graph on the right above is\r\n" );
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document.write( "\"C%28matrix%281%2C3%2C++-8-3sqrt%2813%29%2C+%22%2C%22%2C+6%2Bsqrt%2813%29+%29%29\"\r\n" );
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document.write( "using the -, substitute in\r\n" );
document.write( "\"p\"\"%22%22=%22%22\"\"10-3q\"\r\n" );
document.write( "\"p\"\"%22%22=%22%22\"\"+10-3%286-sqrt%2813%29%29+%5D\"\r\n" );
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document.write( "\"p\"\"%22%22=%22%22\"\"10-18%2B3sqrt%2813%29%29\"\r\n" );
document.write( "\"p\"\"%22%22=%22%22\"\"-8%2B3sqrt%2813%29%29\"\r\n" );
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document.write( "So point C in the graph on the left above is\r\n" );
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document.write( "\"C%28matrix%281%2C3%2C++-8%2B3sqrt%2813%29%2C+%22%2C%22%2C+6-sqrt%2813%29+%29%29\"\r\n" );
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document.write( "Now we will find the midpoint of CD which will be K,\r\n" );
document.write( "where the two diagonals intersect.\r\n" );
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document.write( "We will find K for the graph on the left.\r\n" );
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document.write( "For the graph on the left\r\n" );
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document.write( "\"C%28matrix%281%2C3%2C++-8%2B3sqrt%2813%29%2C+%22%2C%22%2C+6-sqrt%2813%29+%29%29\" and D(3,9)\r\n" );
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document.write( "Using the midpoint formula:\r\n" );
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document.write( "Midpoint = \r\n" );
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document.write( "Midpoint = \r\n" );
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document.write( "Midpoint = \r\n" );
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document.write( "For the graph on the right\r\n" );
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document.write( "\"C%28matrix%281%2C3%2C++-8-3sqrt%2813%29%2C+%22%2C%22%2C+6%2Bsqrt%2813%29+%29%29\" and D(3,9)\r\n" );
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document.write( "Using the midpoint formula:\r\n" );
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document.write( "Midpoint = \r\n" );
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document.write( "Midpoint = \r\n" );
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document.write( "Midpoint = \r\n" );
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document.write( "Edwin
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