document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=885735>Question 885735</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One alloy of iron consists 49% iron & another 28% irob.How many tons should be used to make 120 tons of 42% iron alloy? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #535435 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=535435\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One alloy of iron consists 49% iron & another 28% irob.How many tons should be used to make 120 tons of 42% iron alloy?<BR>\n" );
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document.write( "let x=amt of 49% iron to use<BR>\n" );
document.write( "120-x=amt of 28% iron to use<BR>\n" );
document.write( "..<BR>\n" );
document.write( "49%x+28%(120-x)=42%*120<BR>\n" );
document.write( ".49x+33.6-.28x=50.4<BR>\n" );
document.write( ".21x=16.8<BR>\n" );
document.write( "x=80<BR>\n" );
document.write( "120-x=40<BR>\n" );
document.write( "amt of 49% iron to use=80 tons<BR>\n" );
document.write( "amt of 28% iron to use=40 tons<BR>\n" );
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