document.write( "Question 885699: At what air speed must a plane be flown to complete a trip between two airports 420 miles apart in 5 hours if the flight going has a head wind (blowing against the nose of the plane) of 40 mph and the flight returning has a tail wind of 30 mph? \n" ); document.write( "
Algebra.Com's Answer #535431 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
At what air speed must a plane be flown to complete a trip between two airports 420 miles apart in 5 hours if the flight going has a head wind (blowing against the nose of the plane) of 40 mph and the flight returning has a tail wind of 30 mph?
\n" ); document.write( ":
\n" ); document.write( "let s = air speed required for this scenario
\n" ); document.write( "then
\n" ); document.write( "(s-40) = ground speed against the wind
\n" ); document.write( "and
\n" ); document.write( "(s+30) = ground speed with the wind
\n" ); document.write( ":
\n" ); document.write( "Write a time equation; time = dist/speed
\n" ); document.write( "\"420%2F%28%28s-4%29%29%29\" + \"420%2F%28%28s%2B30%29%29\" = 5
\n" ); document.write( "multiply by (s-40)(s+30)
\n" ); document.write( "(s-40)(s+30)*\"420%2F%28%28s-40%29%29%29\" + (s-40)(s+30)*\"420%2F%28%28s%2B30%29%29\" = 5(s-40)(s+30)
\n" ); document.write( ":
\n" ); document.write( "Cancel the denominators, FOIL the right side, resulting in:
\n" ); document.write( "420(s+30) + 420(s-40) 5(s^2+30s-40s-1200)
\n" ); document.write( ":
\n" ); document.write( "420s + 12600 + 420s - 16800 5(s^2 - 10s - 1200)
\n" ); document.write( ":
\n" ); document.write( "840s - 4200 = 5s^2 - 50s - 6000
\n" ); document.write( "0 = 5s^2 - 50s - 840s - 6000 + 4200
\n" ); document.write( "0 = 5s^2 - 890s - 1800
\n" ); document.write( "simplify divide by 5
\n" ); document.write( "s^2 - 178s - 360 = 0
\n" ); document.write( "You can us the quadratic formula here but this will factor to
\n" ); document.write( "(s-180) (s+2) = 0
\n" ); document.write( "the positive solution
\n" ); document.write( "s = 180 mph is the air speed of the aircraft
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check this by finding the flight time for each way
\n" ); document.write( "420/140 = 3 hr (40 mph head wind)
\n" ); document.write( "420/210 = 2 hr (30 mph tail wind)
\n" ); document.write( "------------------
\n" ); document.write( "total time 5 hrs
\n" ); document.write( "
\n" ); document.write( "
\n" );