document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=9954>Question 9954</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given the following, evaluate cos\r<BR>\n" );
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document.write( "cos= 1/2\r<BR>\n" );
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document.write( "tan is negative? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #5354 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=5354\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> i am assuming i have understood your stripped down version of the question... Also look into my Lesson of Trig equations, as the explanation is there, more than what i will explain here.\r<BR>\n" );
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document.write( "Let angle be A, so cosA=1/2...what is the angle if tanA is negative.\r<BR>\n" );
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document.write( "Well, from your calculator, angle A is 60 degrees but if we do tan60, we get a positive angle.\r<BR>\n" );
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document.write( "Question is, where is cos +ve but tan -ve? Answer is the 4th quadrant, so the angle we require is actually 300 degrees...\r<BR>\n" );
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document.write( "cos300 --> +1/2<BR>\n" );
document.write( "tan300 is -ve\r<BR>\n" );
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document.write( "jon.<BR>\n" );
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