document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=885762>Question 885762</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a certain field is a rectangle with a perimeter of 934 feet.the length is 179 feet more than the width.find the width of the rectanglar field </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #535398 by </B><A HREF=/tutors/aboutme.mpl?userid=basketball1127><B>basketball1127(19)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=basketball1127><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=535398\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = length of field<BR>\n" );
document.write( "    y = width of field\r<BR>\n" );
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document.write( "Then<BR>\n" );
document.write( "x = y + 179\r<BR>\n" );
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document.write( "2x + 2y = 934<BR>\n" );
document.write( "x + y = 467\r<BR>\n" );
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document.write( "Substituting,<BR>\n" );
document.write( "(y + 179) + y = 467<BR>\n" );
document.write( "2y + 179= 467<BR>\n" );
document.write( "2y = 467 - 179<BR>\n" );
document.write( "2y = 288<BR>\n" );
document.write( "y = 144\r<BR>\n" );
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document.write( "width = 144ft </SPAN>\n" );
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