document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=885754>Question 885754</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the measures of two angles are in the ratio 4:5 .The larger of the two angles is 60 less than twice the smaller angle.Find the measure of the angle.Are the angles complementary or supplementary? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #535397 by </B><A HREF=/tutors/aboutme.mpl?userid=basketball1127><B>basketball1127(19)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=basketball1127><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=535397\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let 4x= measure of smaller angle<BR>\n" );
document.write( "    5x= measure of larger angle\r<BR>\n" );
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document.write( "Then<BR>\n" );
document.write( "5x=2(4x)-60°<BR>\n" );
document.write( "5x=8x-60°<BR>\n" );
document.write( "8x-5x=60°<BR>\n" );
document.write( "3x=60°<BR>\n" );
document.write( "x=20°<BR>\n" );
document.write( "smaller angle = 4x = 4(20°) = 80°<BR>\n" );
document.write( "larger angle= 5x = 5(20°) = 100°\r<BR>\n" );
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document.write( "100°+80°=180°<BR>\n" );
document.write( "Therefore the angles are supplementary\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );