document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=885558>Question 885558</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of three numbers is 59. the second is 6 more than the first. the thrid is 1 more than the twice and first. find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #535366 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=535366\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of three numbers is 59. the second is 6 more than the first. the thrid is 1 more than the twice and first. find the numbers.<BR>\n" );
document.write( "***<BR>\n" );
document.write( "let x=1st number<BR>\n" );
document.write( "x+6=2nd number<BR>\n" );
document.write( "2x+1=3rd number<BR>\n" );
document.write( "..<BR>\n" );
document.write( "x+x+6+2x+1=59<BR>\n" );
document.write( "4x=52<BR>\n" );
document.write( "x=13<BR>\n" );
document.write( "x+6=19<BR>\n" );
document.write( "2x+1=27<BR>\n" );
document.write( "1st number=13<BR>\n" );
document.write( "2nd number=19<BR>\n" );
document.write( "3rd number=27 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );