document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=885695>Question 885695</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If each of two opposite sides of a square is increased by 3 centimetres and each of the other two sides is decreased by 2 centimetres, the area is increased by 8 square centimetres.  Find the length of a side of the square.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #535365 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=535365\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If each of two opposite sides of a square is increased by 3 centimetres and each of the other two sides is decreased by 2 centimetres, the area is increased by 8 square centimetres. Find the length of a side of the square. <BR>\n" );
document.write( "***<BR>\n" );
document.write( "let x=length of a side of the square.<BR>\n" );
document.write( "..<BR>\n" );
document.write( "area of a rectangle=length*width<BR>\n" );
document.write( "(x+3)(x-2)-x^2=8<BR>\n" );
document.write( "x^2+x-6-x^2=8<BR>\n" );
document.write( "x-6=8<BR>\n" );
document.write( "x=14<BR>\n" );
document.write( "length of a side of the square=14 cm </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );