document.write( "Question 885669: Find the zeros of the function algebraically.
\n" ); document.write( "f(x)=x^3-x^2-25x+25 \n" ); document.write( "

Algebra.Com's Answer #535341 by Theo(13342) $\"\"$ $\"About$

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f(x) = x^3 - x^2 - 25x + 25
\n" ); document.write( "set it equal to zero to get:
\n" ); document.write( "x^3 - x^2 - 25x + 25 = 0
\n" ); document.write( "separate into 2 parts as shown below:
\n" ); document.write( "(x^3 - x^2) - (25x - 25) = 0
\n" ); document.write( "factor out x^2 in the left part and factor out 25 in the right part to get:
\n" ); document.write( "x^2 * (x - 1) - 25 * (x - 1) = 0
\n" ); document.write( "factor out the common (x-1) term to get:
\n" ); document.write( "(x^2 - 25) * (x - 1) = 0
\n" ); document.write( "factor (x^2 - 25) to get:
\n" ); document.write( "(x - 5) * (x + 5) * (x - 1) = 0
\n" ); document.write( "those are your factors.
\n" ); document.write( "the zeroes are:
\n" ); document.write( "x = 5
\n" ); document.write( "x = -5
\n" ); document.write( "x = 1
\n" ); document.write( "a graph of your equation looks like this:
\n" ); document.write( " $\"$$$\"$
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