document.write( "Question 885668: Bret started on a 80-mile bicycle ride at 15 miles per hour. After a time he became a little tired and slowed down to 10 miles per hour for the rest of the trip. The entire trip of 80 miles took
\n" ); document.write( "5 1/2 hours. How far had Bret ridden when he reduced his speed to 10 miles per hour?
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Algebra.Com's Answer #535339 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+d+\" = distance Bret had traveled
\n" ); document.write( "at \"+15+\" mi/hr
\n" ); document.write( "Let \"+t+\" = time spent traveling at
\n" ); document.write( "\"+15+\" mi/hr
\n" ); document.write( "\"+80+-+d+\" = distance Bret traveled at
\n" ); document.write( "\"+10+\" mi/hr
\n" ); document.write( "\"+5.5+-+t+\" = time spent traveling at
\n" ); document.write( "\"+10+\" mi/hr
\n" ); document.write( "----------------
\n" ); document.write( "Equation for riding at 15 mi/hr:
\n" ); document.write( "(1) \"+d+=+15t+\"
\n" ); document.write( "Equation for riding at 10 mi/hr
\n" ); document.write( "(2) \"+80+-+d+=+10%2A%28+5.5+-+t+%29+\"
\n" ); document.write( "(2) \"+80+-+d+=+55+-+10t+\"
\n" ); document.write( "(2) \"+d+-+10t+=+25+\"
\n" ); document.write( "---------------------
\n" ); document.write( "Substitute (1) into (2)
\n" ); document.write( "(2) \"+d+-+10t+=+25+\"
\n" ); document.write( "(2) \"+15t+-+10t+=+25+\"
\n" ); document.write( "(2) \"+5t+=+25+\"
\n" ); document.write( "(2) \"+t+=+5+\"
\n" ); document.write( "(1) \"+d+=+15t+\"
\n" ); document.write( "(1) \"+d+=+15%2A5+\"
\n" ); document.write( "(1) \"+d+=+75+\"
\n" ); document.write( "----------------
\n" ); document.write( "Bret had ridden 75 mi at 15 mi/hr
\n" ); document.write( "check:
\n" ); document.write( "\"+80+-+d+=+80+-+75+\"
\n" ); document.write( "\"+80+-+d+=+5+\"
\n" ); document.write( "----------------
\n" ); document.write( "(2) \"+80+-+75+=+10%2A%28+5.5+-+5+%29+\"
\n" ); document.write( "(2) \"+5+=+10%2A.5+\"
\n" ); document.write( "(2) \"+5+=+5+\"
\n" ); document.write( "OK\r
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