document.write( "Question 885635: Joe bought a 1 kilogram block of cheese that was 12cm * 10cm * 8cm.
\n" ); document.write( "When he needed to use it, he found mould on each face of the block. To remove the mould, Joe cut a 1 cm thick slice from each face.
\n" ); document.write( "What was the mass of the remaining block of cheese, in grams? \n" ); document.write( "

Algebra.Com's Answer #535337 by KMST(5328) $\"\"$ $\"About$

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Joe started with a block of cheese with a volume of
\n" ); document.write( " $\"%2812cm%29%2810cm%29%288cm%29=960\"$ $\"cm%5E3\"$
\n" ); document.write( "Joe ended with a block of cheese with sides measuring
\n" ); document.write( " $\"12cm-2cm=10cm\"$ ,
\n" ); document.write( " $\"10cm-2cm=8cm\"$ , and
\n" ); document.write( " $\"8cm-2cm=6cm\"$ .
\n" ); document.write( "The volume of the final, remaining block of cheese is
\n" ); document.write( " $\"%2810cm%29%288cm%29%284cm%29=480\"$ $\"cm%5E3\"$ .
\n" ); document.write( "The final, remaining block of cheese has half the volume of the original block of cheese,
\n" ); document.write( "so its weight must be half the weight of the original block of cheese.
\n" ); document.write( "The remaining block of cheese as a mass of half a kilogram, or $\"highlight%28500g%29\"$ .
\n" ); document.write( "
\n" ); document.write( "NOTE:
\n" ); document.write( "The multiplications for both volumes were easy, but not necessary
\n" ); document.write( "The remaining block, as a fraction of the original block is
\n" ); document.write( " $\"%2810cm%29%288cm%29%286cm%29%2F%28%2812cm%29%2810cm%29%288cm%29%29\"$ =

= $\"6%2F12=1%2F2\"$
\n" ); document.write( " \n" ); document.write( "

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