document.write( "Question 885650: Problem : A candidate who gets 36% marks in an examination fails by 24 marks but another candidate who gets 43% marks,gets 18 more marksthan the minimum pass marks. Find the maximum marks and the percentage of pass marks. \n" ); document.write( "
Algebra.Com's Answer #535322 by Theo(13342)\"\" \"About 
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x = maximum marks that can be gotten.
\n" ); document.write( "y = passing marks
\n" ); document.write( "first equation is:
\n" ); document.write( ".36 * x = y - 24
\n" ); document.write( "second equation is:
\n" ); document.write( ".43 * x = y + 18
\n" ); document.write( "solve for y in the first equation to get:
\n" ); document.write( "y = .36 * x + 24
\n" ); document.write( "substitute for y in the second equation to get:
\n" ); document.write( ".43 * x = .36 * x + 24 + 18
\n" ); document.write( "simplify to get:
\n" ); document.write( ".43 * x = .36 * x + 42
\n" ); document.write( "subtract .36 * x from both sides of this equation to get:
\n" ); document.write( ".07 * x = 42
\n" ); document.write( "divide both sides of this equation by .07 to get:
\n" ); document.write( "x = 600
\n" ); document.write( "the most marks that can be gotten is 600.
\n" ); document.write( "substitute for x in the first equation to get:
\n" ); document.write( ".36 * x = y - 24 becomes:
\n" ); document.write( ".36 * 600 = y - 24
\n" ); document.write( "simplify to get:
\n" ); document.write( "216 = y - 24
\n" ); document.write( "add 24 to both sides of this equation to get:
\n" ); document.write( "y = 240
\n" ); document.write( "that's the passing mark.
\n" ); document.write( "the passing percent is 240 / 600 = .4 = 40%
\n" ); document.write( "your solutions are:
\n" ); document.write( "maximum marks = 600
\n" ); document.write( "passing mark percent = 40%\r
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