document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=885602>Question 885602</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Angelo took a group of people to the movies and spent $80 on tickets. Adult tickets cost $10, and child tickets cost $6. The equation to represent his cost is 10A + 6C = $80. If there were 5 children in the group, how many adult tickets did he purchase? Show your work and use a complete sentence to explain your solution in the context of the original problem. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #535293 by </B><A HREF=/tutors/aboutme.mpl?userid=indra89811><B>indra89811(24)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=indra89811><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=indra89811><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=535293\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The no. of children is given as 5, hence the variable C can be replaced by 5 i.e plugging in C=5 in this equation 10 A + 6 C = 80, we get<BR>\n" );
document.write( "10 A + 6*5=80<BR>\n" );
document.write( "10A=50<BR>\n" );
document.write( "A=5<BR>\n" );
document.write( "Hence, 5 adult tickets were purchased.\r<BR>\n" );
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document.write( "---------------Peace out, hun ;D -------------------------- </SPAN>\n" );
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