document.write( "Question 885506: the diagonal of a rectangle is 36cm long. if the rectangle is twice as long as it is wide find the width of the rectangle \n" ); document.write( "
Algebra.Com's Answer #535288 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! the diagonal of a rectangle is 36cm long. \n" ); document.write( "if the rectangle is twice as long as it is wide find the width of the rectangle \n" ); document.write( ": \n" ); document.write( "Let x = the width \n" ); document.write( "then \n" ); document.write( "(2x) = the length \n" ); document.write( ": \n" ); document.write( "Using pythag: a^2 + b^2 = c^2, where \n" ); document.write( "a = x \n" ); document.write( "b = (2x) \n" ); document.write( "c = 36 \n" ); document.write( ": \n" ); document.write( "x^2 + (2x)^2 = 36^2 \n" ); document.write( "x^2 + 4x^2 = 1296 \n" ); document.write( "5x^2 = 1296 \n" ); document.write( "x^2 = 1296/5 \n" ); document.write( "x^2 = 259.2 \n" ); document.write( "x = \n" ); document.write( "x = 16.1 is the width \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "You can check this for yourself: does 16.1^2 + 32.2^2 = 36^2? \n" ); document.write( " |