document.write( "Question 885506: the diagonal of a rectangle is 36cm long. if the rectangle is twice as long as it is wide find the width of the rectangle \n" ); document.write( "
Algebra.Com's Answer #535288 by ankor@dixie-net.com(22740)\"\" \"About 
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the diagonal of a rectangle is 36cm long.
\n" ); document.write( "if the rectangle is twice as long as it is wide find the width of the rectangle
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\n" ); document.write( "Let x = the width
\n" ); document.write( "then
\n" ); document.write( "(2x) = the length
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\n" ); document.write( "Using pythag: a^2 + b^2 = c^2, where
\n" ); document.write( "a = x
\n" ); document.write( "b = (2x)
\n" ); document.write( "c = 36
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\n" ); document.write( "x^2 + (2x)^2 = 36^2
\n" ); document.write( "x^2 + 4x^2 = 1296
\n" ); document.write( "5x^2 = 1296
\n" ); document.write( "x^2 = 1296/5
\n" ); document.write( "x^2 = 259.2
\n" ); document.write( "x = \"sqrt%28259.2%29\"
\n" ); document.write( "x = 16.1 is the width
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\n" ); document.write( "You can check this for yourself: does 16.1^2 + 32.2^2 = 36^2?
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