document.write( "Question 885592: there are three consecutive odd integers. if we take the difference of the third and the first integers, it becomes equal to the product of the first and second integers plus the square of the second integer. what is the third odd integer?\r
\n" ); document.write( "\n" ); document.write( "hint: x be the first integer
\n" ); document.write( " x+2 be the second odd integer
\n" ); document.write( " x+4 be the third odd integer \n" ); document.write( "

Algebra.Com's Answer #535286 by MathTherapy(10552) $\"\"$ $\"About$

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there are three consecutive odd integers. if we take the difference of the third and the first integers, it becomes equal to the product of the first and second integers plus the square of the second integer. what is the third odd integer?\r
\n" ); document.write( "\n" ); document.write( "hint: x be the first integer
\n" ); document.write( " x+2 be the second odd integer
\n" ); document.write( " x+4 be the third odd integer
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document.write( "Since x is the 1st integer, then 2nd = x + 2, and 3rd = x + 4
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document.write( "Therefore, 
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document.write( "2x(x + 3) = 0\r
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document.write( "x + 3 = 0                OR          2x = 0
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document.write( "x = - 3                  OR          x = 0 (ignore)\r
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document.write( "Third ODD integer: - 3 + 4, or  \n" );
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