document.write( "Question 885564: in triangle abc, the measure of angle b is three times that of angle a. the measure of angle c is 20 degrees more than that of angle a. find angles a,b,c. \n" ); document.write( "

Algebra.Com's Answer #535263 by algebrapro18(249) $\"\"$ $\"About$

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Well lets start off by stating that the sum of the angles in a triangle need to add up to 180 degrees. Lets let the measure of angle a = x. Then the measure of angle b = 3x and the measure of angle c = 20+x. Now we just add these and set the sum equal to 180 and solve for x.
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\n" ); document.write( "\n" ); document.write( "x+3x+20+x = 180 combining like terms
\n" ); document.write( "5x+20 = 180 subtracting 20 from both sides
\n" ); document.write( "5x = 160 dividing both sides by 5
\n" ); document.write( "x = 32
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\n" ); document.write( "\n" ); document.write( "So we now know that the measure of angle a is 32 degrees. That means that the measure of angle b is 32*3 = 96 degrees and that the measure of angle c is 20+32 = 52 degrees. \n" ); document.write( "

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